Lucas Bouquet vs Ryan Nijboer: Where to Watch, Predictions, Stats

Bet nowGamble Responsibly 18+
Tennis Maia Challenger Men Lucas Bouquet - Ryan Nijboer
Result
1:2
25/11/2024 at 07:00 (Time Zone – GMT-5 (America/New_York))
  • CHALLENGER MEN - SINGLES: Maia (Portugal) - Qualification, clay (indoor) - Final
Lucas Bouquet - Ryan Nijboer - Gamble Responsibly 18+
00:00 / 90:00
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Match Stats

Aces
110
Double Faults
64
1st Serve Percentage
53%64%
1st Serve Points Won
60% (28/47)73% (36/49)
2nd Serve Points Won
34% (14/41)41% (11/27)
Break Points Saved
50% (8/16)33% (2/6)
1st Return Points Won
27% (13/49)45% (21/47)
2nd Return Points Won
59% (16/27)66% (27/41)
Break Points Converted
67% (4/6)50% (8/16)
Service Points Won
46% (40/87)61% (46/75)
Return Points Won
39% (29/75)54% (47/87)
Total Points Won
43% (69/162)57% (93/162)
Last 10 Balls
19
Match Points Saved
00
Service Games Won
43% (6/14)69% (9/13)
Return Games Won
31% (4/13)57% (8/14)
Total Games Won
37% (10/27)63% (17/27)

Chances of winning


Lucas Bouquet
27.3%
Ryan Nijboer
72.7%

Initial Probability

(when we started the analysis)
35.6% 64.4%

Our Initial ML Estimation

38% 62%


Analysis of Changes in Winning Probabilities:

  • Lucas Bouquet has seen a decrease in its chances compared to the initial analysis. (-8.3%)
  • Note: This is a significant drop in prediction, indicating that Lucas Bouquet's form might have worsened.
  • Ryan Nijboer has improved its chances compared to the initial analysis. (+8.3%)
  • Note: This is a significant improvement in prediction, suggesting Ryan Nijboer's recent form is better than expected.
  • ML Model estimates a higher probability for Lucas Bouquet than the current prediction. (+10.7%)
  • Note: The ML model's higher estimate suggests a strong performance forecast for Lucas Bouquet, possibly due to key factors that the model accounted for.
  • ML Model estimates a lower probability for Ryan Nijboer than the current prediction. (-10.7%)
  • Note: The ML model's lower estimate suggests a potential downturn for Ryan Nijboer, possibly due to injuries or other negative factors.
  • Lucas Bouquet - Ryan Nijboer Odds

    1 X 2 Marga
    Avarage Now
    (Initially)
    3.42
    (2.61)

    1.28
    (1.44)
    7.3%
    (7.6%)
    What is the prediction for Lucas Bouquet - Ryan Nijboer?
    The most likely score is 0:2. User prediction is Lucas Bouquet will win! (7 of 7 users predict this).
    Preview Facts
    • Bouquet is ranked ATP: 527. Nijboer is ranked ATP: 389.
    • The game of competitors is shaky now.
    • Bouquet could have advantage in physics - more days for rest in last days.
    • Nijboer will have a small advantage in this match.
    • Recently, the players did not play each other.
    Latest results of Lucas Bouquet
    Latest results of Ryan Nijboer
    Draw
    Singles - Main

    1/16-finals
    1Marti Pujolras A. (Q)Araujo P. (WC)0 : 2
    2Martin A. (Q)Rocha F. (WC)2 : 0
    3Alvarez Varona N. (Q)Gakhov I. (Alt)2 : 0
    4Matusevich A. (LL)Rocha H. (8)1 : 2
    5Passaro F. (4)Janvier M.2 : 0
    6Gaubas V. (LL)Butvilas E.2 : 0
    7Sels J. (Alt)Merida Aguilar D. (Alt)0 : 2
    8Martin Tiffon P.Moller E. (6)2 : 1
    9Ramos A. (5)Sanchez Izquierdo N. (Q)2 : 0
    10Rincon D.Yevseyev D.2 : 1
    11Nijboer R. (Q)Ovcharenko O. (Q)0 : 2
    12Ferreira Silva F. (WC)Dzumhur D. (3)1 : 2
    13Moro Canas A. (7)Shelbayh A.2 : 0
    14Coppejans K. (PR)Vincent Ruggeri S.2 : 0
    15Andreev A.Debru G. (Alt)2 : 0
    16Blancaneaux G. (RET.)Coria F. (2)0 : 1

    1/8-finals
    1Araujo P.Martin A.1 : 2
    2Alvarez Varona N.Rocha H. (8)0 : 2
    3Passaro F. (4)Gaubas V.2 : 1
    4Merida Aguilar D.Martin Tiffon P.2 : 0
    5Ramos A. (5)Rincon D.2 : 1
    6Ovcharenko O.Dzumhur D. (3)0 : 2
    7Moro Canas A. (7)Coppejans K.0 : 2
    8Andreev A.Coria F. (WO.) (2)

    Quarter-finals
    1Martin A.Rocha H. (8)2 : 0
    2Passaro F. (4)Merida Aguilar D.2 : 0
    3Ramos A. (5)Dzumhur D. (3)0 : 2
    4Coppejans K.Coria F. (2)1 : 2

    Semi-finals
    1Martin A.Passaro F. (4)1 : 2
    2Dzumhur D. (3)Coria F. (2)2 : 0

    Final
    1Passaro F. (4)Dzumhur D. (3)0 : 2
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