Kokoro Isomura vs Xirui Han: Where to Watch, Predictions, Stats

Bet nowGamble Responsibly 18+
Tennis ITF M25 Luan Men Kokoro Isomura - Xirui Han
Result
2:1
12/03/2025 at 03:35 (Time Zone – GMT-4 (America/New_York))

Additional information

  • ITF MEN - SINGLES: M25 Luan (China), hard - 1/16-finals
Kokoro Isomura - Xirui Han - Gamble Responsibly 18+
00:00 / 90:00
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Match Stats

Last 10 Balls
82

Chances of winning


Kokoro Isomura 88.9%Xirui Han 11.1%

Initially Probability

(when we started the analysis)
Kokoro Isomura 89%Xirui Han 11%

Kokoro Isomura - Xirui Han Odds

1 X 2 Marga
Avarage Now
(Initially)
1.04
(1.05)

8.35
(8.5)
7.8%
(7%)
Preview Facts
  • Isomura is ranked ATP: 454. Han is ranked ATP: 1618.
  • Recent matches Isomura is playing changeable (in the last 5 games wins - 3).
  • In this match Isomura is the unquestionable favorite.
  • Recently, the players did not play each other.
Latest results of Kokoro Isomura
Latest results of Xirui Han
19.09.2024 Aziz Dougaz - Xirui Han 2:0
17.09.2024 Hanyi Liu - Xirui Han 1:2
30.05.2024 Zhenxiong Dong - Xirui Han 2:1
Draw
2025

1/16-finals
1Noguchi R. (1)Visker N.2 : 0
2Xiao L.Ehrenschneider N.0 : 2
3Wang C.Santillan A.0 : 2
4Tokuda R.Agafonov E. (8)1 : 2
5Imamura M. (4)Sun Z.2 : 1
6Motta A.Zhang T.0 : 2
7Ianin N.Lu P.1 : 2
8Trongcharoenchaikul W.Crawford O. (6)0 : 2
9Uchida K. (5)Saitoh K.2 : 1
10Leong M. W. K.Zhukov M.2 : 0
11Takahashi Y.Jiang F.2 : 0
12Ichikawa T.Cui J. (3)0 : 2
13Isomura K. (7)Han X.2 : 1
14Zheng Z.Chung H.0 : 2
15Mo Y. C.Chiu J.2 : 0
16Tang S.Bai Y. (2)0 : 2

1/8-finals
1Noguchi R. (1)Ehrenschneider N.2 : 0
2Santillan A.Agafonov E. (8)2 : 1
3Imamura M. (4)Zhang T.0 : 2
4Lu P.Crawford O. (6)1 : 2
5Uchida K. (5)Leong M. W. K.2 : 0
6Takahashi Y.Cui J. (3)1 : 2
7Isomura K. (7)Chung H.1 : 2
8Mo Y. C.Bai Y. (2)0 : 2

Quarter-finals
1Noguchi R. (1)Santillan A.0 : 2
2Zhang T.Crawford O. (6)0 : 2
3Uchida K. (5)Cui J. (3)0 : 2
4Chung H.Bai Y. (2)2 : 0

Semi-finals
1Santillan A.Crawford O. (6)1 : 2
2Cui J. (3)Chung H.0 : 2

Final
1Crawford O. (6)Chung H.2 : 1
X
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