Karl Poling vs Nicholas Heng: Where to Watch, Predictions, Stats

Bet nowGamble Responsibly 18+
Tennis ITF M15 Rochester Ny Men Karl Poling - Nicholas Heng
Result
1:2
16/07/2024 at 10:40 (Time Zone – GMT-4 (America/New_York))
  • ITF MEN - SINGLES: M15 Rochester, NY (USA), clay - 1/16-finals
Karl Poling - Nicholas Heng - Gamble Responsibly 18+
00:00 / 90:00
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Match Stats

Max Games In Row
22

Chances of winning


Karl Poling 76.6%Nicholas Heng 23.4%

Initially Probability

(when we started the analysis)
Karl Poling 66.7%Nicholas Heng 33.3%

Karl Poling - Nicholas Heng Odds

1 X 2 Marga
Avarage Now
(Initially)
1.24
(1.38)

4.04
(2.77)
8.5%
(5.7%)
Preview Facts
  • Recent matches Poling is playing shaky (in the last 5 games wins - 3).
  • Poling could have problems with physics compare with it opponent - last days they played more matches than their opponents.
  • In this match Poling is a favorite.
  • Recently, the players did not play each other.
Latest results of Karl Poling
Latest results of Nicholas Heng
Draw
2024

1/16-finals
1Sinclair C. (1)Bruce C. (Q)2 : 1
2Sarr J.Filin N.2 : 0
3Poling K.Heng N.1 : 2
4Falck R. (Q)Banerjee S. (7)0 : 2
5Grant W. (3)Stice T.2 : 0
6Tudorica A. N. (Q)Finkelstein A. (Q)2 : 0
7Carpenter M.Bernard A.0 : 2
8Van Orderlain D.Martin D. (6)0 : 2
9George B. T. (8)Vakili K.2 : 0
10Southcombe M.Burnett E. (Q)1 : 2
11Benjamin J.Byers L. T. (Q)0 : 2
12Godsick N.Gomez E. (4)2 : 0
13Sinha A. (5)Gaal C.1 : 2
14Brown L. (Q)Zink T.0 : 2
15Hashimoto H. (Q)Fishback R.2 : 0
16Fahim I. M.Descotte M. F. (2)0 : 2

1/8-finals
1Sinclair C. (1)Sarr J.2 : 1
2Heng N.Banerjee S. (7)0 : 2
3Grant W. (3)Tudorica A. N.1 : 2
4Bernard A.Martin D. (6)2 : 1
5George B. T. (8)Burnett E.2 : 0
6Byers L. T.Godsick N.2 : 1
7Gaal C.Zink T.0 : 2
8Hashimoto H.Descotte M. F. (2)0 : 2

Quarter-finals
1Sinclair C. (1)Banerjee S. (7)0 : 2
2Tudorica A. N.Bernard A.0 : 2
3George B. T. (8)Byers L. T.2 : 0
4Zink T.Descotte M. F. (2)2 : 0

Semi-finals
1Banerjee S. (7)Bernard A.0 : 2
2George B. T. (8)Zink T.0 : 2

Final
1Bernard A.Zink T.2 : 0
X
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